3.63 \(\int \frac {x^3}{(a x+b x^2)^{5/2}} \, dx\)

Optimal. Leaf size=23 \[ \frac {2 x^3}{3 a \left (a x+b x^2\right )^{3/2}} \]

[Out]

2/3*x^3/a/(b*x^2+a*x)^(3/2)

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Rubi [A]  time = 0.01, antiderivative size = 23, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {650} \[ \frac {2 x^3}{3 a \left (a x+b x^2\right )^{3/2}} \]

Antiderivative was successfully verified.

[In]

Int[x^3/(a*x + b*x^2)^(5/2),x]

[Out]

(2*x^3)/(3*a*(a*x + b*x^2)^(3/2))

Rule 650

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(e*(d + e*x)^m*(a +
b*x + c*x^2)^(p + 1))/((p + 1)*(2*c*d - b*e)), x] /; FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b^2 - 4*a*c, 0] &&
EqQ[c*d^2 - b*d*e + a*e^2, 0] &&  !IntegerQ[p] && EqQ[m + 2*p + 2, 0]

Rubi steps

\begin {align*} \int \frac {x^3}{\left (a x+b x^2\right )^{5/2}} \, dx &=\frac {2 x^3}{3 a \left (a x+b x^2\right )^{3/2}}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 21, normalized size = 0.91 \[ \frac {2 x^3}{3 a (x (a+b x))^{3/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[x^3/(a*x + b*x^2)^(5/2),x]

[Out]

(2*x^3)/(3*a*(x*(a + b*x))^(3/2))

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fricas [A]  time = 0.97, size = 35, normalized size = 1.52 \[ \frac {2 \, \sqrt {b x^{2} + a x} x}{3 \, {\left (a b^{2} x^{2} + 2 \, a^{2} b x + a^{3}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/(b*x^2+a*x)^(5/2),x, algorithm="fricas")

[Out]

2/3*sqrt(b*x^2 + a*x)*x/(a*b^2*x^2 + 2*a^2*b*x + a^3)

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giac [B]  time = 0.22, size = 89, normalized size = 3.87 \[ \frac {2 \, {\left (3 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a x}\right )}^{2} b^{\frac {3}{2}} + 3 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a x}\right )} a b + a^{2} \sqrt {b}\right )}}{3 \, {\left ({\left (\sqrt {b} x - \sqrt {b x^{2} + a x}\right )} \sqrt {b} + a\right )}^{3} b^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/(b*x^2+a*x)^(5/2),x, algorithm="giac")

[Out]

2/3*(3*(sqrt(b)*x - sqrt(b*x^2 + a*x))^2*b^(3/2) + 3*(sqrt(b)*x - sqrt(b*x^2 + a*x))*a*b + a^2*sqrt(b))/(((sqr
t(b)*x - sqrt(b*x^2 + a*x))*sqrt(b) + a)^3*b^2)

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maple [A]  time = 0.05, size = 25, normalized size = 1.09 \[ \frac {2 \left (b x +a \right ) x^{4}}{3 \left (b \,x^{2}+a x \right )^{\frac {5}{2}} a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3/(b*x^2+a*x)^(5/2),x)

[Out]

2/3*(b*x+a)*x^4/a/(b*x^2+a*x)^(5/2)

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maxima [B]  time = 1.39, size = 74, normalized size = 3.22 \[ -\frac {x^{2}}{{\left (b x^{2} + a x\right )}^{\frac {3}{2}} b} - \frac {a x}{3 \, {\left (b x^{2} + a x\right )}^{\frac {3}{2}} b^{2}} + \frac {2 \, x}{3 \, \sqrt {b x^{2} + a x} a b} + \frac {1}{3 \, \sqrt {b x^{2} + a x} b^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/(b*x^2+a*x)^(5/2),x, algorithm="maxima")

[Out]

-x^2/((b*x^2 + a*x)^(3/2)*b) - 1/3*a*x/((b*x^2 + a*x)^(3/2)*b^2) + 2/3*x/(sqrt(b*x^2 + a*x)*a*b) + 1/3/(sqrt(b
*x^2 + a*x)*b^2)

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mupad [B]  time = 0.30, size = 24, normalized size = 1.04 \[ \frac {2\,x\,\sqrt {b\,x^2+a\,x}}{3\,a\,{\left (a+b\,x\right )}^2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3/(a*x + b*x^2)^(5/2),x)

[Out]

(2*x*(a*x + b*x^2)^(1/2))/(3*a*(a + b*x)^2)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{3}}{\left (x \left (a + b x\right )\right )^{\frac {5}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3/(b*x**2+a*x)**(5/2),x)

[Out]

Integral(x**3/(x*(a + b*x))**(5/2), x)

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